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Jawaban: #1:
Kode : 12.2.1 [Kelas 12 Matematika BAB 1 – Integral]
Pembahasan [tex] \int\ \fracx^3(x^4-3)^6 \, dx [/tex]
Metoda substitusi
u = x⁴ – 3
[tex] \fracdudx=4x^3 [/tex]
[tex]dx= \fracdu4x^3 [/tex]
[tex]= \int\ (x^3)(x^4-3)^-6 } \, dx[/tex]
[tex]= \int\ (x^3)u^-6 } \, \fracdu4x^3 [/tex]
[tex]= \frac14 \int\ u^-6} } \, du[/tex]
[tex]=(\frac14) (\frac1-5)u^-5} } +c[/tex]
[tex]=-\frac120u^-5} } +c[/tex]
[tex]=- \frac120(x^4-3)^-5+c [/tex]
[tex]=- \frac120(x^4-3)^5+c [/tex]
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